For the network of capacitors shown, find the equivalent capacitance and the total charge when connected to a 36 V source. Note that C1 = C2 = 4.0 F and C3 = C4 = 6.0 F.
C12=C1+C2=8 F,C_{12}=C_1+C_2=8~F,C12=C1+C2=8 F,
C34=C3+C4=12 F,C_{34}=C_3+C_4=12~F,C34=C3+C4=12 F,
C=C12C34C12+C34=4.8 F,C=\frac{C_{12}C_{34}}{C_{12}+C_{34}}=4.8~F,C=C12+C34C12C34=4.8 F,
q=CU=173 C.q=CU=173~C.q=CU=173 C.
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