Answer to Question #326635 in Electricity and Magnetism for Anna

Question

1. A proton (charge +𝑒=1.602 𝑥 10^−19 𝐶) moves a distance d = 0.30 m in a straight line between points a and b in a linear accelerator. The electric field is uniform along this line, with magnitude 𝐸= 2.1 𝑥 10^7 𝑁/𝐶 in the direction from a to b. Determine: (a) the force on the proton; (b) the work done on it by the field; (c) the potential difference

2. What is the potential difference between two point in an electric field if it takes 500J of energy to move a charge of 2.5C between these two points?

Answer 1

1.

$F=eE=3 .4~pN,$

$A=Fd=1~pJ,$

$U=\frac Aq=6 .3~MV.$

2.

$U=\frac Aq=200~V.$