A copper wire has a resistance of 15.0 at a temperature of 14 degrees * C . After a current passes through the windings, the resistance rose to 22.5 ohms. To what temperature was the wire heated?
t2=t1+R2−R1αR1=146°C.t_2=t_1+\frac{R_2-R_1}{\alpha R_1}=146°C.t2=t1+αR1R2−R1=146°C.
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