Question #323956

Radiation with a frequency of 7.52 × 1014 Hz illuminates a photoelectric surface in a photoelectric cell. If the work function of this surface is 2.20 eV, what is the maximum kinetic energy of the emitted electrons, and what stopping voltage would be required to reduce the current through this cell to zero?

Expert's answer

E=10 kJ

U=3.5 eV


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