Question #323946

Two-point charges, q1, which has a charge of -76.11 uC and q2, which has a charge of 13.33 uC, are separated by a distance of 24.67 cm. Identify the field's magnitude at point A between the two charges if A is 10.39 cm away from the negative charge.


1
Expert's answer
2022-04-06T14:03:34-0400

We know that


E1=kq1r2E1=9×109×76.11×1060.10392=634.53×105N/CE_1=\frac{kq_1}{r^2}\\E_1=-\frac{9\times10^9\times76.11\times10^{-6}}{0.1039^2}=-634.53\times10^{5}N/C

Electric field due to charge q2


E2=kq2r2E2=9×109×13.33×1060.35062=9.759×105N/CE_2=\frac{kq_2}{r^2}\\E_2=\frac{9\times10^9\times13.33\times10^{-6}}{0.3506^2}=9.759\times10^5N/C

Enet=E1+E2E_{net}=E_1+E_2


Enet=(634.53+9.759)×105=624.77×105N/CE_{net}=(-634.53+9.759)\times10^5=-624.77\times10^{5}N/C



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Comments

Draken
08.04.22, 03:26

Thank you very much!

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