Question #320798

The speed of a car is decreased uniformly from 30 meters per second to 10 meters per second in 4 seconds. The magnitude of the car's acceleration in m/s^2 is


Expert's answer

v=u+at

Acceleration

a=vuta=\frac{v-u}{t}

a=10304=204=5m/sec2a=\frac{10-30}{4}=\frac{-20}{4}=-5m/sec^2

Deaccleration


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