3. How many excess electrons must be added to an isolated spherical conductor 0.100 meters in diameter to produce an electric field of 1800 N/C just outside the surface?
Answer
No of electrons added to sphere
N=ER2Ke=1800∗0.05∗0.059∗109∗1.6∗10−19=31∗106N=\frac{ER^2}{Ke}\\=\frac{1800*0.05*0.05}{9*10^9*1.6*10^{-19}}\\=31*10^6N=KeER2=9∗109∗1.6∗10−191800∗0.05∗0.05=31∗106
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