. A battery that has q=10000 C
q=10000 C and ΔV=12 V
ΔV=12 V. Find the total electric potential energy.
Answer
the total electric potential energy
U=qΔV2=10000∗122=60000JU=\frac{qΔV}{2}\\=\frac{10000*12}{2}\\=60000JU=2qΔV=210000∗12=60000J
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