Find the pull on the plunger of an electromagnet when the total flux uniformly distributed is 0.8 mWb. The diameter of the plunger is 5 cm.
Answer
That pulling force is given by
F=ϕ22Aμ0=0.8∗0.8∗10−62∗3.14∗0.05∗0.05∗4∗3.14∗10−7=129.69NF=\frac{\phi^2}{2A\mu_0}\\=\frac{0.8*0.8*10^{-6}}{2*3.14*0.05*0.05*4*3.14*10^{-7}}\\=129.69NF=2Aμ0ϕ2=2∗3.14∗0.05∗0.05∗4∗3.14∗10−70.8∗0.8∗10−6=129.69N
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