Question

A solenoid has a magnetic reluctance of 0.0022. It has 300 turns. If the current flowing is 0.5 A, find the total flux in max wells.

Answer 1

Reluctance

$r=\frac{I}{\mu_0 A}$

$A=\frac{I}{\mu_0 r}$

$$A=\frac{0.5}{4\times3.14\times10^{-7}\times0.0022}=18.09\times\times10^{7}m^2$$

Magnetic field

$B=\mu_0 ni$

$$B=4\times3.14\times10^{-7}\times300\times0.5=1.884\times10^{-4}T$$

Magnetic flux

$$\phi=BA=1.884\times10^{-4}\times18.09\times10^{7}=34.081\times10^{3}T$$