Question

1.0 Three equal charges of +6 nC are located at the corners of an equilateral triangle (3) whose sides are 12 cm long, as shown below. Find the potential at the center of the triangle.

Answer 1

Potential

$V_1=V_2=V_3=\frac{kq}{r}$

$V_1=V_2=V_3=\frac{9\times10^9\times6\times10^{-9}\times\sqrt3}{0.12}$

$V_1=V_2=V_3=779.42V$

$$V=V_1+V_2+V_3=779.42+779.42+779.42$$

$V=2338.26V$