Question #314599

The series combination of 5 F and 20 F capacitors is connected in parallel to 4 F capacitor. What is the equivalent capacitance

1
Expert's answer
2022-03-20T18:48:07-0400

C=5⋅205+20+4=8 F,C=\frac{5\cdot 20}{5+20}+4=8~F,

q=CU=8⋅100=800 C.q=CU=8\cdot 100=800~C.

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