Answer to Question #313275 in Electricity and Magnetism for Rajat Vats

Question #313275

If the current (I) in a long solenoid is doubled and number of turns per unit length (n) are halved, find the effect on the magnetic field (i) inside and (ii) outside the solenoid.


1
Expert's answer
2022-03-21T12:47:22-0400

Solenoid magnetic field

B=μ0NiLB=\frac{\mu_0Ni}{L}

Inside


B=μ0niB=\mu_0 ni

B=μ0niB'=\mu_0n'i'

B=μ0×n2×2iB'=\mu_0\times\frac{n}{2}\times2i

BB=11\frac{B'}{B}=\frac{1}{1}

B=BB'=B

Part(b)

Out side

Bo=0TB_o=0T

Outside magnetic field of solenoid at any point zero

Bo=0TB_o=0T


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