Two point charges reacted with each other to produce 4.32 x 10⁻⁴ J. the magnitude of q
is 27 nC with a distance from the point charge of 19 cm. Find the magnitude of the point
charge
The potential energy of the system of charges is given by
"E_p=k\\frac{q_1q_2}{r}"Hence
"q_2=\\frac{E_pr}{kq_1}""q_2=\\frac{4.32*10^{-4}*0.19}{9*10^9*27*10^{-9}}=3.4*10^{-7}\\:\\rm C"
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