Find the charge stored in a capacitor with a capacitance of 50 uF and a potential difference of 10 V.( In C and uC)
Answer
the charge stored in a capacitor
Q=CV=50∗10−6∗10=0.5mCQ=CV\\=50*10^{-6}*10\\=0.5mCQ=CV=50∗10−6∗10=0.5mC
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