Question #310556

A train moves from an observer standing on a platform with a velocity of 10m/s. The siren emitted by the Train has a frequency of 50Hz.

A. What is the frequency of the sound heard by the observer?

B. What is the frequency of the sound heard by the observer in the Train?

(SPEED OF SOUND = 330 PER SECONDS)


1
Expert's answer
2022-03-13T18:50:31-0400

Formula Doppler effect


ν=ν0v+v1vv2\nu=\nu_{0} \cdot \frac{v+v_1}{v-v_2}

ν\nu - frequency of sound heared by observer

ν0\nu_0 - frequency of sound from source

vv - velocity of sound

v1v_1 - velocity of observer when it move to the source (else it will be negative)

v2v_2 - velocity of source when it move to the observer ( else it will be negative)

Answer A

ν=ν0vvv2\nu=\nu_0 \frac{v}{v-v_2}

Calculating


ν=50330330(10)=48,5Hz\nu=50 \frac{330}{330-(-10)}=48,5 Hz

Answer B

ν=ν0v+v1vv2\nu=\nu_0 \frac{v+v_1}{v-v_2}

The observer moves in train


v1=v2v_1=v_2

Calculating

ν=50330+10330(10)=50Hz\nu=50 \cdot\frac{330+10}{330-(-10)}=50 Hz


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