What is the force on na electron in an electric field of 200 N/C?
Answer
the force on an electron in an electric field of 200 N/C
F=qE=1.6∗10−19∗200=320∗10−19NF=qE\\=1.6*10^{-19}*200\\=320*10^{-19}NF=qE=1.6∗10−19∗200=320∗10−19N
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