Two-point charges reacted with each other to produce 4.32 x 10⁻⁴ J. the magnitude of q is 30 nC with a distance from the point charge of 19 cm. Find the magnitude of the point charge
Answer
The another charge is given by
Q=4.32∗10−4∗0.199∗109∗30∗10−9=3.04nCQ=\frac{4.32*10^{-4}*0.19}{9*10^9*30*10^{-9}}\\=3.04nCQ=9∗109∗30∗10−94.32∗10−4∗0.19=3.04nC
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