Find the electric flux through a cylinder with a distance of 22 cm and a height of 35 cm with a charge of 5.42 μC. ( use the general formula of flux and the area of cylinder is 2𝜋rh + 2𝜋r²)
Answer
Using gauss law flux can be written as
ϕ=qϵ0=5.42∗10−68.85∗10−12=0.61∗106Wb\phi=\frac{q}{\epsilon_0}\\=\frac{5.42*10^{-6}}{8.85*10^{-12}}\\=0.61*10^{6}Wbϕ=ϵ0q=8.85∗10−125.42∗10−6=0.61∗106Wb
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments