Answer to Question #308285 in Electricity and Magnetism for yengg

Question #308285

What is the electric field strength at a point 40 cm from a charge of 5x10⁹ C?

1
Expert's answer
2022-03-09T12:30:46-0500

Electric field

E=kqr2E=\frac{kq}{r^2}

Put value


E=9×109×5×1090.42=2.82×1020N/CE=\frac{9\times10^9\times5\times10^9}{0.4^2}=2.82\times10^{20}N/C


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