Question

What would be the PE of a -5nC charge placed at this point?

Answer 1

Now we know that

At point P potential

$V=V_p$

$V_p=\frac{kq}{r}$

Potential energy

$U=-q∆V$

$$U=-(-5\times10^{-9}\times V_p)=5\times10^{-9}V_p J$$