Question #308282

Find the potential at a distance of 0.07m from a -6nC charge.





1
Expert's answer
2022-03-09T12:30:52-0500

Potential

V=kQrV=\frac{kQ}{r}

V=−9×109×6×10−90.07=−771.42CV=-\frac{9\times10^9\times6\times10^{-9}}{0.07}=-771.42C


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