What is the force on an electron in an electric field of 500 N/C?
A charge of 5 X 10-6 C experiences a force of 10 N at a certain point in space. What is the electric field intensity?
1.
F=eE=80⋅10−18 N.F=eE=80\cdot 10^{-18}~N.F=eE=80⋅10−18 N.
2.
E=Fq=2 MNC.E=\frac Fq=2~\frac{MN}C.E=qF=2 CMN.
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