:An attractive force of 12kN is experienced by two charges of magnitude 4nC and 7nC. At what
distance must these two charges be to experience this force?
Answer
Distance
r=9∗109∗4∗7∗10−1812000=4.5∗10−6mr=\sqrt{\frac{9*10^9*4*7*10^{-18}}{12000}}\\=4.5*10^{-6}mr=120009∗109∗4∗7∗10−18=4.5∗10−6m
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments