Two point charges ares separated by a distance of one meter .The two point charges have magnitudes of 2.5x10^-4 C and 1.5 x10^-2 C.Find the electric force between the two. Round your final answer to it's nearest hundreths.
Answer
Force between them
F=9∗109∗2.5∗10−4∗1.5∗10−21=33.75∗104NF=\frac{9*10^9*2.5*10^{-4}*1.5* 10^{-2} }{1}\\=33.75*10^4NF=19∗109∗2.5∗10−4∗1.5∗10−2=33.75∗104N
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