Calculate the total force on charge A. All three charges are 2.5uC. The distance from A to B is 2.0 m and from B to C is 2.0 m and angle B is 90°
F1=kq2r12=14.06 mN,F_1=\frac{kq^2}{r_1^2}=14.06~mN,F1=r12kq2=14.06 mN,
F2=kq2r22=7.03 mN,F_2=\frac{kq^2}{r_2^2}=7.03~mN,F2=r22kq2=7.03 mN,
F=F12+F22+2F1F2cos45°=19.67 mN.F=\sqrt{F_1^2+F_2^2+2F_1F_2\cos45°}=19.67~mN.F=F12+F22+2F1F2cos45°=19.67 mN.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments