A wire having the diameter of 1.2 mm and resistively of 100 * 10 ^ - 1 * Omega * m at 0°C is connected. across a cell of emf
1.5 V and gives a current of 10 mA. Calculate the length of the wire.
We know that
V=iR
R=VIR=\frac{V}{I}R=IV
R=1.50.01=150ΩR=\frac{1.5}{0.01}=150\OmegaR=0.011.5=150Ω
R=ρlAR=\frac{\rho l}{A}R=Aρl
l=RAρl=\frac{RA}{\rho}l=ρRA
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