Question

find the total capacitance for three capacitors connected in series, given their individual capacitances are 1.0 F, 5.0 F, and 8.0 F. ( 0.755 microfarad)

Answer 1

Answer

the total capacitance for three capacitors connected in series

$C_t=\frac{1*5*8}{1*5+5*8+8*1}\\=0.755mF$