Answer to Question #303887 in Electricity and Magnetism for kirby

Question

What is the magnitude of the electric force of attraction between an iron nucleus

(q = −26e) and its innermost electron if the distance between them is 1.5 × 10−12m?

Answer 1

Answer

the magnitude of the electric force

$F=\frac{KQq}{r^2}\\= \frac{9*10^9*26*1.6*10^{-19}*1.6*10^{-19}}{1.5*1.5*10^{-24}}\\=0.00234N$