Question

A point charge has a charge of 8.00 x 10-11 C. At what distance from the point charge is the electrical potential (a) 12.0 V? (b) 24.0 V?

Answer 1

Answer.

Distance is given

$r=\frac{kQ}{V}$

a) the distance

$r=\frac{9*10^9*8*10^{-11}}{12}\\=6cm$

b) the potential

$r=\frac{9*10^9*8*10^{-11}}{24}\\=3cm$