Question #302980

2 charged particles reacted with a force of 0.31 N with a distance of 1.5 cm, the 2nd charge contains 54 nC. Find the value of the first charge.


Expert's answer

q2=Fr2kq1=143.5 nC.q_2=\frac{Fr^2}{kq_1}=143.5~nC.


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