Question

The ratio of number of electronic states in the energy range 2-3 eV to that of in 0-3 eV ((Number of electronic states in the energy range 2 -3 eV)/(Number of electronic states in the energy range 0-3 eV)) will be

Answer 1

$p=\frac{n_{2-3}}{n_{0-3}}=1-\frac{2^2}{3^2}=0.56.$