a charge of 20 x 10-6 c is 20 cm from another charge of 60 x 10-6 c. (b) determine the ep midway between them.
Answer
Charges are same nature so electric field is in opposite direction.
So net electric field at mid point
Ep=9∗109(0.01)2∗(60−20)∗10−6=36∗106N/CE_p=\frac{9*10^9}{(0.01) ^2}*(60-20) *10^{-6}\\=36*10^6N/CEp=(0.01)29∗109∗(60−20)∗10−6=36∗106N/C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments