Answer to Question #301479 in Electricity and Magnetism for aisme

Question

An isotope ²⁴Mg moves through a velocity selector of a mass spectrometer has an electric field of 150 Vcm^-1 and a magnetic field of 0.70 T. Calculate the velocity of the isotope that exits the velocity selector.

Answer 1

Answer

velocity of the isotope that exits the velocity selector

$v=\frac{E}{B}\\=\frac{15000}{0.70}\\=21,428.57m/s$