Question

A plane of two turns coil of area 0.0127 m² is placed in a uniform magnetic field of 0.7 T. The current in the coils is 3 A. If the plane makes an angle of 50° with the magnetic field, calculate the torque exerted on the coil.

Answer 1

Answer

torque exerted on the coil

$\tau=NIABsin\theta$

Putting all values

$\tau=2*3*0.0127*0.7*\sin50°\\=253.34Nm$