Question

A point charge 𝑞1 = +6.00 𝑥 10−9𝐶 is at the point 𝑥 = 0.800 𝑚, 𝑦 = 0.600 𝑚 and a second point charge 𝑞2 = −2.00 𝑥 10−9𝐶 is at the point 𝑥 = 0.800 𝑚, 𝑦 = 0 𝑚. Calculate the magnitude and direction of the resultant electric field at the origin due to these charges.

Answer 1

$E_1=\frac{kq_1}{r_1^2}=54.0~\frac NC,$

$E_2=\frac{kq_2}{r_2^2}=28.1~\frac NC,$

$E=\sqrt{E_1^2+E_2^2+2E_1E_2\sin\varphi}=35.7~\frac NC.$