Question

A point charge 𝑞 = 8.00 𝑥 10−9𝐶 is at the center of the cube with sides of length 0.200 m. What is the electric flux through one of the six faces of the cube?

Answer 1

Answer

$\phi=\frac{Q}{\epsilon_0}\\=\frac{8.00 *10^{-9}}{8.85*10^{-12}}\\=903.95Wb$

the electric flux through one of the six faces of the cube

$=\frac{903.95Wb}{6}\\=150.66Wb$