The relative permittivity of a dielectric is 2.25
a) what is its permittivity?
b)What will be the capacitance if its dielectric is inserted into 7.8 uFair capacitor?
Answer
a) so permittivity of dielectric
ϵ=ϵ0ϵr=8.85×10−12×2.25=19.91×10−12C2/m2.N\epsilon=\epsilon_0 \epsilon_r\\=8.85\times10^{-12}\times2.25\\=19.91\times10^{-12}C^2/m^2.Nϵ=ϵ0ϵr=8.85×10−12×2.25=19.91×10−12C2/m2.N
b) capacitance become
C′=2.25×7.8μF=17.55μFC'=2.25\times7.8\mu F\\=17.55\mu FC′=2.25×7.8μF=17.55μF
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