Question #299875

The parallel plates of an air capacitor are separated by 2.25 mm.Each plate carries a charge of 6.50nC.The manitude of the electric field of the plates is 4.74x10^5V/m.Find the a) potential difference between he plates



b) capacitance and



c)area of the plate.

1
Expert's answer
2022-02-20T08:20:19-0500

a)

U=Ed=1067 V,U=Ed=1067~V,

b)

C=qU=6.1 pF,C=\frac q U=6.1~pF,

c)

S=Cdε0=15.5 cm2.S=\frac{Cd}{\varepsilon_0}=15.5~cm^2.


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