Answer to Question #299189 in Electricity and Magnetism for Sim

Question #299189

Assume a point charge Q1 is at x=0 and a charge Q2 is at x= d. What is the relationship between these charges if the resulting electric field is zero at the following points:

a) x= d/2; b) x= 2d; c) x= -d/2


1
Expert's answer
2022-02-18T08:22:35-0500

First let us remind the expression of the total field at the point xx :

E=14πϵ0(Q1xx3+Q2(xd)xd3)E= \frac{1}{4\pi\epsilon_0} (\frac{Q_1 x}{|x|^3}+\frac{Q_2 (x-d)}{|x-d|^3})

  1. The first case gives us Q1d2/4Q2d2/4=0\frac{Q_1}{d^2/4}-\frac{Q_2}{d^2/4}=0 which yields Q1=Q2Q_1=Q_2
  2. The second case gives Q14d2+Q2d2=0\frac{Q_1}{4d^2}+\frac{Q_2}{d^2}=0 which yields Q1=4Q2Q_1=-4Q_2
  3. The third case gives Q1d2/4+Q29d2/4=0\frac{-Q_1}{d^2/4}+\frac{-Q_2}{9d^2/4}=0 which yields Q1=Q2/9Q_1=-Q_2/9

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