Question

1.   Three point charged particles are arranged in a line as shown in the figure below. Charge A = -5 µC, charge B = +10 µC, and charge C = -12 µC. Calculate the net electrostatic force on particle B due to the other two charges.

Answer 1

Answer

Let these charges are at r distance and due to properties of charges

Net force on charge B

is given by

$F=\frac{kB}{r^2}*(C-A)$

Putting all values

$F=\frac{9*10^9*10*10^{-6}}{r^2}*(12-5)*10^{-6}\\=\frac{0.63}{r^2}N$