(I) Four point charges are located at the vertices of a square with side L.
We give q2 = q3 = Q and q1= q4 = −2Q.
Determine the resulting electric field (a) at point A,
in the center of the square; (b) at point B
E⃗=E⃗1+E⃗2+E⃗3+E⃗4,\vec E=\vec E_1+\vec E_2+\vec E_3+\vec E_4,E=E1+E2+E3+E4,
a)
E=22kqL2,E=2\sqrt 2\frac {kq}{L^2},E=22L2kq,
b)
Ex=8kq55L2,E_x=\frac{8kq}{5\sqrt 5 L^2},Ex=55L28kq,
Ey=4kq(55−3)55L2,E_y=\frac{4kq(5\sqrt 5 -3)}{5\sqrt 5 L^2},Ey=55L24kq(55−3),
E=Ex2+Ey2=4kq(138−305)55L2.E=\sqrt{E_x^2+E_y^2}=\frac{4kq(138-30\sqrt 5)}{5\sqrt 5L^2}.E=Ex2+Ey2=55L24kq(138−305).
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments