Answer to Question #295836 in Electricity and Magnetism for Faxzy

Electricity and Magnetism

Question #295836

Calculate the electric field due to a charge of 35uc when it experiences an electrostatic force of 2×10^3N when placed in a vacuum.

Expert's answer

"E=\\frac Fq=\\frac{2\\cdot 10^3}{35\\cdot 10^{-6}}=57.1~\\frac{MV}m."

Learn more about our help with Assignments: Electromagnetism

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Two point charges are located on the positive x-axis of a co-ordinate system. Charge is 2.0cm from
2. Find the total work done in moving a particle in a force field given by F = 2xyî + 3zĵ+ 5xk̂alo
3. Two charges lie on positive x-axis. Charge A (2.0 x 10-9 C) is 2.0 cm from the origin and Charge B i
4. three point charges, which are equally separated by a distance 20 cm, are arranged along the y-axis
5. Four charges, q_{1} = 5.00 * 10 ^ - 7 * C q_{2} = - 3.00 * 10 ^ - 7 * C , q_{3} = - 2.00 * 10 ^ - 7
6. A point particle of charge 2.5 nC and mass 3.25x10^-3 kg is in uniform electric field directed to th
7. Find the flux through the top,left and right side of a cube of side 0.5 m when placed in a horizonta