Find the flux through the top,left and right side of a cube of side 0.5 m when placed in a horizontal uniform electric field of 8.0N/C directed to the right.
Answer
Area of top, left, right surface of cube
A=0.25m2
Electric field E=8.0N/C
Angle between all surface
"\\theta=90\u00b0"
So electric flux is given in all cases
"\\phi=E.A=EA cos\\theta\\\\=8.0\\times0.25\\times cos0\u00b0\\\\=0Wb"
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