Two tiny, identical metal balls carry charges of 6.0 and -14.0 , and are 4 cm apart from each other. What is the force of attraction between these balls?
F=kq1q2r2=472.5 N.F=\frac{kq_1q_2}{r^2}=472.5~N.F=r2kq1q2=472.5 N.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments