Calculate the electric field experienced by a negative test charge given that source charge is +6.78 π₯ 10β15πΆ and 7.9 π₯ 10β19π as the distance from the source charge
Electric field
"E=\\frac{Kq}{r^2}"
"E=\\frac{9\\times10^9\\times6.78\\times10^{-15}}{(7.9\\times10^{-19})^2}"
"E=9.77\\times10^{31}N\/c"
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