Calculate the electric field experienced by a negative test charge given that source charge is +6.78 π₯ 10β15πΆ and 7.9 π₯ 10β19π as the distance from the source charge
Electric field
E=Kqr2E=\frac{Kq}{r^2}E=r2Kqβ
E=9Γ109Γ6.78Γ10β15(7.9Γ10β19)2E=\frac{9\times10^9\times6.78\times10^{-15}}{(7.9\times10^{-19})^2}E=(7.9Γ10β19)29Γ109Γ6.78Γ10β15β
E=9.77Γ1031N/cE=9.77\times10^{31}N/cE=9.77Γ1031N/c
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