Question #293498

Calculate the electric field experienced by a negative test charge given that source charge is +6.78 𝑥 10−15𝐶 and 7.9 𝑥 10−19𝑚 as the distance from the source charge


1
Expert's answer
2022-02-03T12:48:34-0500

Electric field

E=Kqr2E=\frac{Kq}{r^2}

E=9×109×6.78×1015(7.9×1019)2E=\frac{9\times10^9\times6.78\times10^{-15}}{(7.9\times10^{-19})^2}

E=9.77×1031N/cE=9.77\times10^{31}N/c


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