Question #292169

12. Find the potential drop along a copper wire 500 m long and 2 mm in diameter if the current in it is equal to 2 A


Expert's answer

Solution

Length of wire l=500m

Radius R=1mm

So area A=πr2=3.14×1mm×1mmA=\pi r^2=3.14\times1mm\times1mm

A=3.14×10−6m2A=3.14\times10^{-6}m^2

Resistivity of copper wire

ρ=1.68∗10−8Ω−m\rho=1.68 * 10^{-8} Ω -m

So potential difference of wire

V=IR=IρlAV=IR\\=\frac{I\rho l}{A}

Putting all values

V=2×1.68∗10−8×5003.14×10−6=5.35VoltsV=\frac{2\times1.68 * 10^{-8}\times500 }{3.14\times10^{-6}}\\=5.35Volts


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