How many coulontos of charge move across a 120 V source when 1440 J of energy is
required?
The energy, voltage and charge are related as
"\\Delta E = q\\cdot \\Delta V \n\\\\ \\text{}\n\\\\ \\therefore q = \\frac{\\Delta E }{ \\Delta V}= \\frac{1440\\,J }{ 120\\,V}= 12 \\frac{\\cancel{J }}{ \\cancel{J}\/C}= 12\\,C"
Therefore, the amount of charge moved is 12 Coulombs.
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