19. Find the capacitance of the Earth .the radius of the Earth is 6,400 km.By how much will the Earth`s potential chance if it receives a quantity of electricity equal to1C?
C=4πϵ0RC=4\pi \epsilon_0RC=4πϵ0R
Put value
C=6400×1039×109=7.11×10−4FC=\frac{6400\times10^3}{9\times10^9}=7.11\times10^{-4}FC=9×1096400×103=7.11×10−4F
Potential changes
Q=C∆VQ=C∆VQ=C∆V
∆V=17.11×10−4=1406.25V∆V=\frac{1}{7.11\times10^{-4}}=1406.25V∆V=7.11×10−41=1406.25V
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