Find the potential drop along a copper wire 500 m long and 2 mm in diameter if the current in it is equal to 2 A. Determine the potential drop in resistors. ρ(copper)=1.68×10−8 (Ω·m)Energy of charged capacitor.
U=IR=4Iρlπd2=5.3 V.U=IR=\frac{4I\rho l}{\pi d^2}=5.3~V.U=IR=πd24Iρl=5.3 V.
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